Calculate the equilibrium constant for the reaction- 3Sns-2Cr2O72-28 H- 3 Sn-4-4Cr3-14H2O E- for Sn-Sn2-0-136 V E- for Sn2-Sn4-0-154 V E- for Cr2O72-Cr3-1-33 V- if the ans is K-10c- what is c-

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Nernst Equation

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Question

Calculate the equilibrium constant for the reaction:
$3 S n (s) + 2 C r_{2} O_{7}^{2 -} + 28 H^{+} \to 3 S n^{+ 4} + 4 C r^{3 +} + 14 H_{2} O$
$E^{\circ}$ for $S n / S n^{2 +} = 0.136 V E^{\circ}$ for $S n^{2 +} / S n^{4} = - 0.154 V$
$E^{\circ}$ for $C r_{2} O_{7}^{2 -} / C r^{3 +} = 1.33 V$ , if the ans is $K = 10^{c}$ , what is c?

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3 S n + 2 C r_{2} O_{7}^{2 -} + 28 H^{+} \to 3 S n^{4 +} + 4 C r^{3 -} + 14 H_{2} O

E_{S n / S n^{4 +}}^{o} = 0.009 V

E_{C r_{2} O_{7}^{2 -} / C r^{3 -}}^{o} = 1.33 V

S n (s) + 2 H^{+} \to S n^{2 +} + H_{2} (g) a t 25^{\circ} C

E^{\circ} (S n^{2 +} | S n) = 0.14

P b + S n^{2 +} \to P b^{2 +} + S n

\frac{[P b^{2 +}]}{[S n^{2 +}]}

E_{c e l l} = 0

E_{P b / P b^{2 +}}^{\circ} = 0.13 v o l t

E_{S n^{2 +} / S n}^{\circ} = - 0.14 v o l t

K_{c}

C u^{2 +} (a q) + S n^{2 +} (a q) ⟶ S n^{4 +} (a q) + C u (s)

25^{\circ} C

E_{C u^{2 +} | C u}^{\circ} = 0.34 V; E_{S n^{4 +} | S n^{2 +}}^{\circ} = 0.15 V

298 K

2 F e^{3 +} + S n^{2 +} \to 2 F e^{2 +} + S n^{4 +}

E_{S n^{4 +} / S n^{2 +}}^{\circ} = 0.15 v o l t; E_{F e^{3 +} / F e^{2 +}}^{\circ} = 0.771 v o l t

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