Calculate the equilibrium constant for the reaction Cd2-aq- - Zn-s- - gt- Zn2-aq- - Cd-s- If E0 Cd2-Cd - -0-403 V E0 Zn2-Zn - -0-763 V

Dear Student. At #160;anode #160;:Zn(s) #160; #8594; #160;Zn2+(aq) #160;+ #160;2e #160; #160; #160; #160;E #176;=+0.763 #160;VAt ...

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Standard XII

Chemistry

Equilibrium Constant from Nernst Equation

Calculate the...

Question

Calculate the equilibrium constant for the reaction
Cd2+(aq) + Zn(s) ----> Zn2+(aq) + Cd(s)
If E0 Cd2+/Cd = -0.403 V
E0 Zn2+/Zn = -0.763 V

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Solution

Dear Student.

$At anode : Zn (s) \to {Zn}^{2 +} (aq) + 2 e^{-} E ° = + 0.763 V At cathode : {Cd}^{2 +} (aq) + 2 e^{-} \to Cd (s) E ° = - 0.403 V Cell reaction : Zn (s) + {Cd}^{2 +} (aq) \to {Zn}^{2 +} (aq) + Cd (s) E °_{cell} = E °_{cathode} - E °_{anode} = - 0.403 + 0.763 = + 0.360 V and, ∆ G ° = - nFE ° cell and, ∆ G ° = - {RTlnK}_{eq} So, - nFE °_{cell} = - {RTlnK}_{eq} or, K_{eq} = \exp (\frac{nFE °_{cell}}{RT}) or, K_{eq} = \exp (\frac{2 \times 96500 \times 0.360}{8.314 \times 298}) = \exp (28.04) = 1.5 \times 10^{12}$

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Similar questions

Q. Calculate the emf and

Δ G^{o}

for the cell reaction at

25^{o}

Z n (s) | Z n_{a q}^{2 +} (0.1 M) | C d_{a q}^{2 +} (0.01 M) | C d_{(s)}

Given

E^{o} Z n^{2 +} / Z n = - 0.763

and

E^{o} C d^{2 +} / C d = - 0.403 V .

Q. Write cell representation for following cells :

C d^{2 +} (a q) + Z n (s) \to Z n^{2 +} (a q) + C d (s)

Q. The value of equilibrium constant

(K_{f})

for the reaction:

Z n^{2 +} (a q) + 4 O H^{-} (a q) ⇌ Z n (O H)_{4}^{2 -} (a q)

is represented in scientific notation as

p \times 10^{q},

then q is:
Given :

Z n^{2 +} (a q) + 2 e^{-} \to Z n (s); E^{0} = - 0.76 V

Z n (O H)_{4}^{2 -} (a q) + 2 e^{-} \to Z n (s) + 4 O H^{-} (a q); E^{0} = - 1.36 V

2.303 \frac{R T}{F} = 0.06

$E^{0}$ for the cell, $Z n | Z n {^{2 +}}_{(a q)} | | C u {^{2 +}}_{(a q)} | C u$ is $1.10 V$ at $25^{0} C$ . The equilibrium constant for $Z n + C u {^{2 +}}_{(a q)} \to Z n {^{2 +}}_{(a q)} + C u$ the cell reaction is of the order of :

Q. Which of the following statement(s) is/are true?

Z n^{2 +} (a q) + 2 e^{-} \to Z n (s); E^{0} = - 0.76 V

C u^{2 +} (a q) + 2 e^{-} \to C u (s); E^{0} = 0.34 V

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Calculate the equilibrium constant for the reaction Cd2+(aq) + Zn(s) ----> Zn2+(aq) + Cd(s) If E0 Cd2+/Cd = -0.403 V E0 Zn2+/Zn = -0.763 V

Calculate the equilibrium constant for the reaction
Cd2+(aq) + Zn(s) ----> Zn2+(aq) + Cd(s)
If E0 Cd2+/Cd = -0.403 V
E0 Zn2+/Zn = -0.763 V