Calculate the equilibrium constant for the reaction.
$F e^{2 +} + C e^{4 +} | F e^{3 +} + C e^{3 +}$ , [given: $E^{0} C e^{4 +} / C e^{3 +} = 1.44$ V; $E^{0} F e^{3 +} / F e^{2 +} = 0.68 V]$ .

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Solution

$E^{0} {C e}_{4}^{+} / {C e}^{3 +} = 1.44 V$
$E^{0} F e^{3 +} / F e^{2 +} = 0.68 V$
$E_{c e l l}^{0} = E^{0} C {e_{4}}^{+} / C e^{3 +} + E^{0} F e^{3 +} / F e^{2 +}$
$= - 0.68 + 1.44 = 0.76 V$
$E_{c e l l}^{0} = (\frac{0.059}{1}) {log}_{10} K_{c}$
${log}_{10} K_{c} = \frac{0.76}{0.059} = 12.8814$
$K_{c} = 7.6 \times 10_{c e l l}$

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Similar questions

F e^{2 +} + C e^{4 +} ⇌ F e^{3 +} + C e^{3 +}

E_{C e^{4 +} / C e^{3 +}}^{0} = 1.44 V; E_{F e^{3 +} / F e^{2 +}}^{0} = 0.68 V]

F e^{2 +} + C e^{4 +} ⇌ F e^{3 +} + C e^{3 +}

E_{C e^{4 +} / C e^{3 +}}^{o} = 1.44 V; E_{F e^{3 +} / F e^{2 +}}^{o} = 0.68 V

F e^{2 +} + C e^{4 +} ⇌ F e^{3 +} + C e^{3 +}

E_{{C e}^{4 +} / C e^{3 +}}^{\circ} = 1.44 V; E_{F e^{2 +} / F e^{3 +}}^{\circ} = 0.68 V

F e^{2 +} + C e^{4 +} ⇌ F e^{3 +} + C e^{3 +}

E_{C e^{4 +} | C e^{3 +}}^{o} = 1.44 V; E_{F e^{3 +} | F e^{2 +}}^{o} = 0.68 V

F e^{2 +} + C e^{4 +} ⇌ C e^{3 +} + F e^{3 +}

E_{C e^{4 +} / C e^{3 +}}^{\circ} = 1.44 V

E_{F e^{3 +} / F e^{2 +}}^{\circ} = 0.68 V

\frac{2.303 R T}{F} = 0.06

25^{o} C, l o g 4.68 = 0.67

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