Question

Calculate the force between two alpha particles kept at a distance of $0.02$ $mm$ in air.

Answer 1

$q_{\alpha }=+2e$

$F=\frac{1}{4\pi {ϵ}_o}\frac{2e\times 2e}{r^2}$

$\Rightarrow F=\frac{9\times {10}^9\times 2\times 2\times (1.6\times {10}^{-19}{)}^2}{0.02\times 0.02\times {10}^{-6}}$

$\Rightarrow F=1.0368\times {10}^{-26}$ $N$