Question

Calculate the force between two masses of 100 kg and 1000 kg separated by a distance of 10 m ($G=6.67\ast {10}^{-11}$ N $\frac{m^2}{k{g}^2}$).

Answer 1

According to Newton's law of gravitation, force of attraction between two bodies is

$F=\frac{G{m}_1{m}_2}{r^2}$

Here, m1 = 100 kg; m2 = 1000 kg;

r = 10 m; G = $G=6.67\ast {10}^{-11}$ N $\frac{m^2}{k{g}^2}$

$F=\frac{6.67\ast {10}^{-11}\ast 100\ast 100}{{10}^2}$

= $6.67\ast {10}^{-8}$ N