Calculate the force of gravitation between two objects of masses 80 kg and 1200 kg kept at a distance of 10 m from each other.Given ( $G = 6.67 \times 10^{- 11} N m^{2} / k g^{2}$ )

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Solution

Given : $m_{1} = 80 k g$ $m_{2} = 1200 k g$ $d = 10 m$
Force of gravitation $F = \frac{G m_{1} m_{2}}{d^{2}}$
Or $F = \frac{6.67 \times 10^{- 11} \times 80 \times 1200}{10^{2}} = 6.4 \times 10^{- 8} N$

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G = 6.67 \times 10^{- 11} N m^{2} / K g^{2}

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10 g

is kept on the surface of a uniform sphere of mass

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and radius

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(G = 6.67 \times 10^{- 11} \frac{N m^{2}}{k g^{2}})

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Calculate the force of gravitation between two objects of masses 80 kg and 1200 kg kept at a distance of 10 m from each other.Given (G=6.67×10−11 Nm2/kg2)

Given : m1=80 kg m2=1200 kg d=10 mForce of gravitation F=Gm1m2d2Or F=6.67×10−11×80×1200102=6.4×10−8 N

Calculate the force of gravitation between two objects of masses 80 kg and 1200 kg kept at a distance of 10 m from each other.Given ( $G = 6.67 \times 10^{- 11} N m^{2} / k g^{2}$ )

Given : $m_{1} = 80 k g$ $m_{2} = 1200 k g$ $d = 10 m$
Force of gravitation $F = \frac{G m_{1} m_{2}}{d^{2}}$
Or $F = \frac{6.67 \times 10^{- 11} \times 80 \times 1200}{10^{2}} = 6.4 \times 10^{- 8} N$