Question

Calculate the force of attraction between two bodies each weighing 1 kg and separated 1 m apart.

Value of G = $6.67\times {10}^{-11}$M.K.S. units.

Answer 1

Step 1: Given

$$\begin{gathered} Massofboththeobjects, \\ {M}_1=M_2=1kg \\ Dis\tan cebetweenboththeobjects, \\ R=1m \\ G=6.67\times {10}^{-11}N{m}^{2}k{g}^{-2}(inM.K.S.units) \end{gathered}$$

Step 2: Writing the formula for the gravitational force

$F=G\times \frac{M_1\times M_2}{R^2}$

Step 3: Substituting the given values in the formula to find the gravitational force.

$$\begin{gathered} F=G\times \frac{1\times 1}{1^2} \\ =G \\ =6.67\times {10}^{-11}N \end{gathered}$$

Hence, the force between two bodies each weighing 1 kg and separated 1 m apart will be $6.67\times {10}^{-11}$N.