-8203-Calculate the force required to move a train of 2000 quintal nbsp-up an inclined of 1 in 50 with an acceleration of 2ms-2- nbsp- the force of friction being 0-5 Newton per quintal- nbsp- nbsp-

Dear Student, Here given, nbsp; m = 2000 quintals = 2000 X 100 kg sin theta; = 1/50 ; a = 2 ms 2 Force of friction = 0.5 N per quintal F = 0.5 X 2000 = 10 ...

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Standard IX

Physics

Second Law of Motion

#8203;Calcula...

Question

Calculate the force required to move a train of 2000 quintal up an inclined of 1 in 50 with an acceleration of 2ms^-2, the force of friction being 0.5 Newton per quintal.

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Solution

Dear Student,

Here given, m = 2000 quintals = 2000 X 100 kg
sin θ = 1/50 ; a = 2 ms^-2
Force of friction = 0.5 N per quintal
F = 0.5 X 2000 = 1000 N
In moving up an inclined plane, force required against gravity = m g sin θ = 20, 0000 X 9.8 X 1/50 = 39200 N.
Also force required to produce acceleration = m a = 20, 0000 X 2 = 40,0000 N
Therefore, total force required = 1000 + 39200 + 40,0000 = 440200 N .

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​Calculate the force required to move a train of 2000 quintal up an inclined of 1 in 50 with an acceleration of 2ms^-2, the force of friction being 0.5 Newton per quintal.

Calculate the force required to move a train of 2000 quintal up an inclined of 1 in 50 with an acceleration of 2ms^-2, the force of friction being 0.5 Newton per quintal.