Calculate the formality of NaCl solution having 1.78 gm solute dissolved in 178 ml solution.

1.78 F

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16 F

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.17 F

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1.7 F

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
0.17 F

Recollect that,
$F o r m a l i t y = \frac{f o r m u l a m a s s o f s o l u t e}{V o l u m e o f s o l u t i o n (i n l i t r e s)}$

Formula mass of a solute is calculated just like molecular mass, but the only difference is that it is calculated for ionic solids.
$∴$ Formula mass of NaCl = 23 + 35.5 = 58.5
Formality= $\frac{1.78}{58.5} \times \frac{1000}{178} = 0.17 F$

Suggest Corrections

Similar questions

Calculate the formality of NaCl solution having 1.78 gm solute dissolved in 178 ml solution.

2.6 \times 10^{- 3}

Calculate the Normality of a solution having 15 gm equivalents. Dissolved in 750 mL solution.

Calculate Molarity of a solution having 50 milli moles dissolved in 10 mL of solution.

Join BYJU'S Learning Program