Calculate the freezing point of an aqueous solution containing 10.50 g of MgBr2 in 200 g of water (Molar mass of MgBr2 is 184 g) (Kf for water is 1.86 K kg /mol)
dTf = kf*m
dTf = 0.512*(10.50/184)1000/200=0.146’C
dTf =freezing pt. of pure water- Freezing pt. of solution
0.146=0’C-Freezing pt. of solution
Freezing pt. of solution(containing MgBr2)= -0.146 C