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Question

Calculate the freezing point of solution when 1.9 g of MgCl2 (M - 95gmol - 1) was dissolved in 50g of water, assuming MgCl2 undergoes complete ionisation. [Kffor water= 1.86KKgmol1]

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Solution

ΔTf=i Kfm

ΔTf=(3)(1.86)×25

ΔTf=2.232

TinitialTfinal=2.232

Tfinal=Tinitial2.232

Tfinal=0oC2.232oC

Tfinal=2.232oC

Note:
Kf=1.86 KKg.mol1

i=3[MgCl2Mg2++2Cli=2+11=3]

m=Given massMolecular mass×1weight of solvent(kg)

m=1.995×150×1000 mol/kg

m=2050=25 mol/kg

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