Calculate the heat necessary to raise the temperature of 60g of aluminium from 35 -C to 55 -C- Molar heat capacity of al is 24 J-mole - 1 K - 1-

1) No.of moles of Al(m)=60g(27 g #10;mol^ 1) #10; #10; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #1 ...

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Standard XII

Chemistry

Molar and Specific Heat Capacity

Calculate the...

Question

Calculate the heat necessary to raise the temperature of 60g of aluminium from 35 $^{\circ} C$ to 55 $^{\circ} C$ . Molar heat capacity of al is 24 J.mole $^{- 1}$ K $^{- 1}$ .

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Solution

1) No.of moles of $A l (m) = \frac{60 g}{(27 g m o l^{- 1})}$

$= 2.22 m o l$

2) Molar heat capacity(c) $= 24 J m o l^{- 1} K^{- 1}$

Rise in temperature $Δ T = 55 - 35$

$= 20 K$

3) Heat evolved (q) $= C \times m \times T$

$= (24 J m o l^{- 1} K^{- 1}) \times (2.22 m o l) \times (20 K)$

$= 1065.7 J$

$= 1.06 k J$

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Calculate the heat necessary to raise the temperature of 60g of aluminium from 35∘C to 55∘C. Molar heat capacity of al is 24 J.mole −1 K−1.

1) No.of moles of Al(m)=60g(27gmol−1) =2.22mol 2) Molar heat capacity(c)=24Jmol−1K−1 Rise in temperature ΔT=55–35 =20K 3) Heat evolved (q) =C×m×T =(24Jmol−1K−1)×(2.22mol)×(20K) =1065.7J =1.06kJ

Calculate the heat necessary to raise the temperature of 60g of aluminium from 35 $^{\circ} C$ to 55 $^{\circ} C$ . Molar heat capacity of al is 24 J.mole $^{- 1}$ K $^{- 1}$ .