Calculate the heat of formation of acetic acid from the following data- CH3COOHl-2O2g- 2CO2-2H2Ol-i - H -2079kcal Cs-O2g-CO2g- H -94-48kcal-ii H2g-12O2g-H2Ol- H -68-4kcal-iii

The required equation is 2C(s)+2H_2(g)+O_2(g)=CH_3COOH(l); #160;Δ H =? This equation can be obtained by multiplying eq (ii) by 2 and also eq. ...

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Heat of Formation

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Question

Calculate the heat of formation of acetic acid from the following data:
${C H}_{3} C O O H (l) + 2 O_{2} (g) \to 2 {C O}_{2} + 2 H_{2} O (l) . . . . (i) (Δ H = - 2079 k c a l)$
$C (s) + O_{2} (g) \to {C O}_{2} (g); (Δ H = - 94.48 k c a l) . . . (i i)$
$H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l); (Δ H = - 68.4 k c a l) . . . . (i i i)$

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C (S) + O_{2} (g) \to C O_{2} (g)

Δ H = - 94.0 K c a l

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l)

Δ H = - 68.0 K c a l

C H_{3} C O O H (l) + 2 O_{2} (g) \to 2 C O_{2} (g) + 2 H_{2} O (l)

Δ H = - 210.0 K c a l

C H_{3} C O O H (l)

25^{\circ} C

C H_{3} C O O H (l) + 2 O_{2} (g) \to 2 C O_{2} + 2 H_{2} O (l); Δ H = - 208.34

C (s) + O_{2} (g) \to C O_{2} (g); Δ H = - 94.05

H_{2} (g) + \frac{1}{2} O_{2} \to H_{2} O (l); Δ H = - 68.32

C (s) + O_{2} (g) \to C O_{2} (g) Δ H = - 94.0 k c a l

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l) Δ H = - 68.0 k c a l

C H_{3} C O O H (l) + 2 O_{2} (g) \to 2 C O_{2} (g) + 2 H_{2} O (l) Δ H = - 210.0 k c a l

{C H}_{3} O H (l)

{C H}_{3} O H (l) + \frac{3}{2} O_{2} (g) ⟶ C O_{2} (g) + 2 H_{2} O (l); Δ H = - 726 k J

C (s) + O_{2} (g) ⟶ C O_{2} (g); Δ H = - 394 k J

H_{2} (g) + \frac{1}{2} O_{2} (g) ⟶ H_{2} O (l); Δ H = - 286 k J

H_{2} (g) + \frac{1}{2} O_{2} (g) ⟶ H_{2} O (l); Δ H = - 68.4 k c a l

C (g) + O_{2} (g) ⟶ C O_{2} (g); Δ H = - 94.4 k c a l

C_{12} H_{22} O_{11} + 12 O_{2} (g) ⟶ 12 C O_{2} (g) + 11 H_{2} O (g); Δ H = - 1350.0 k c a l

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