Calculate the heat of formation of n-butane from the following data-a- 2C4H10g - 13O2g- 8CO2g - 10H2Ol- - H - -5757-2 kJb- Cs - O2g- CO2g- - H - -405-4 kJc- 2H2g - O2g- 2H2Ol- - H - -572-4 kJ

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Heat of Formation

Calculate the...

Question

Calculate the heat of formation of $n$ -butane from the following data:

a. $2 C_{4} H_{10} (g) + 13 O_{2} (g) ⟶ 8 C O_{2} (g) + 10 H_{2} O (l), Δ H = - 5757.2 k J$

b. $C (s) + O_{2} (g) ⟶ C O_{2} (g), Δ H = - 405.4 k J$

c. $2 H_{2} (g) + O_{2} (g) ⟶ 2 H_{2} O (l), Δ H = - 572.4 k J$

Δ_{f} H = - 174.0 k J m o l^{- 1}

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Δ_{f} H = + 174.0 k J m o l^{- 1}

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Δ_{f} H = - 5930.2 k J m o l^{- 1}

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None of these

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C (s) + O_{2} (g) ⟶ C O_{2} (g)

Δ H = - 393.7 k J

H_{2} (g) + 1 / 2 O_{2} (g) ⟶ H_{2} O (l)

Δ H = - 285.8 k J

C H_{3} C O O H (l) + 2 O_{2} (g) ⟶ 2 C O_{2} (g) + 2 H_{2} O (l)

Δ H = - 873.2 k J

C_{(s)} + O_{2 (g)} \to C O_{2 (g)};

Δ H = - 394 k J

2 H_{2 (g)} + O_{2 (g)} \to 2 H_{2} O_{(l)};

Δ H = - 568 k J

C H_{4 (g)} + 2 O_{2 (g)} \to C O_{2 (g)} + 2 H_{2} O_{(l)};

Δ H = - 394 k J

C H_{4}

C H_{3} C O O H (l)

25^{\circ} C

C H_{3} C O O H (l) + 2 O_{2} (g) \to 2 C O_{2} + 2 H_{2} O (l); Δ H = - 208.34

C (s) + O_{2} (g) \to C O_{2} (g); Δ H = - 94.05

H_{2} (g) + \frac{1}{2} O_{2} \to H_{2} O (l); Δ H = - 68.32

6 C (s) + 3 H_{2} (g) ⟶ C_{6} H_{6} (l), Δ H = 49.0 k J

H_{2} (g) + 1 / 2 O_{2} (g) ⟶ H_{2} O (l), Δ H = - 285.8 k J

C (s) + O_{2} (g) ⟶ C O_{2} (g), Δ H = - 389.3 k J

C (s) + O_{2} (g) \to C O_{2} (g); Δ H = - 394 k J / m o l

2 H_{2} (g) + O_{2} (g) \to 2 H_{2} O (l); Δ H = - 568 k J / m o l

C_{2} H_{5} O H (l) + 3 O_{2} (g) \to 2 C O_{2} (g) + 3 H_{2} O (l); Δ H = - 1058 k J / m o l

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