Question

Calculate the highest frequency of the emitted photon in the Paschen series of spectral lines of the hydrogen atom

• A. $3.7\times {10}^{14}Hz$
• B. $9.1\times {10}^{15}Hz$
• C. $10.23\times {10}^{14}Hz$
• D. $29.7\times {10}^{15}$

Answer 1

The correct option is A $3.7\times {10}^{14}Hz$

frequency of photon for Paschen series is given as $\nu =c{Z}^{2}R(\frac{1}{9}-\frac{1}{n^2})$

$n$ is the orbital quantum number of excited state from where the electron is coming to $3^{rd}$ state

to get the maximum value of $\nu$ take $n\to \infty$

and put $Z=1$ for hydrogen and $R=1.09\times {10}^7$( Rydberg Constant) with $c=3\times {10}^8$ we get $\nu =3.7\times {10}^{14}Hz$