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Question

Calculate the hydrolysis constant of a salt containing NO2 ion. If Ka for HNO2=4.5×1010.

A
2.8×106
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B
20.5×105
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C
2.2×105
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D
1.1×103
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Solution

The correct option is C 2.2×105
NO2 ion hydrolyse as
NO2+H2OHNO2+OH
KH=[HNO2][OH][NO2](1)
Kw=[H+][OH](2)
HNO2 ionizes as follows:
HNO2H++NO2
Ka=[H+][NO2][HNO2](3)
From equations (1) and (3)
KH=KwKa=1×10144.5×1010
=2.22×105

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