Calculate the hydrolysis constant of a salt containing NO−2 ion. If Ka for HNO2=4.5×10−10.
A
2.8×10−6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
20.5×10−5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2.2×10−5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1.1×10−3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C2.2×10−5 NO−2 ion hydrolyse as NO−2+H2O⇌HNO2+OH− KH=[HNO2][OH−][NO−2]……(1) Kw=[H+][OH−]……(2) HNO2 ionizes as follows: HNO2⇌H++NO−2 Ka=[H+][NO−2][HNO2]……(3)
From equations (1) and (3) KH=KwKa=1×10−144.5×10−10 =2.22×10−5