Question

Calculate the hydrostatic pressure exerted by water sideways at the bottom of a beaker. Given that, the depth of water is $10cm$, the density of water is $1000kg{m}^{-3}$and g $=9.8m/s^2$.

Answer 1

Step 1: Given data,

Height of the water column is :

$$\begin{gathered} =10cm \\ =\frac{10}{100}m \end{gathered}$$

Density of water is $\rho =1000kg/m^3$

Acceleration due to gravity is $=9.8m/s^2$

Step 2 : Formula for calculating pressure,

$PressureintheliquidisP=h\rho g$

Now put the values from given data we get

$$\begin{gathered} P=\frac{10}{100}m\times 1000kg/m^3\times 9.8m/s^2 \\ P=980Pa \end{gathered}$$

Hence, he hydrostatic pressure exerted by water sideways at the bottom of a beaker $P=980N/m^{2}orPa$ .