Question

Calculate the magnetic field induction B at the centre of a circular coil having $500$ turns, radius $\pi$ cm and carrying $5$ A of current

• A. $0.1$ T
• B. $0.005$ T
• C. $0.5$ T
• D. $0.05$ T

Answer 1

The correct option is D $0.05$ T

Magnetic field at center due to one ring is $B$.

Hence, due to $n$ ring is $B$,

$B=n{B}_1$

where $n=500$turns.

$B_1=\frac{{\mu }_{0}I}{2r}$ where $I=$current through ring, $r=$radius of ring.

$B=500\times \frac{4\pi \times {10}^{-7}\times 5}{2\times \pi \times {10}^{-2}}=5\times {10}^{-2}=0.05T$