Calculate the magnetic moment of $C r^{3 +}$ .

2.9

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3.57

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4.12

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3.87

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Solution

The correct option is D 3.87
$C r^{3 +}$ [Ar] $3 d^{3}$
no. of unpaired electron= 3
since $μ$ = $\sqrt{n (n + 2)}$
= $\sqrt{3 (3 + 2)}$
=3.87

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