Question

Calculate the magnetic moment of $M{n}^{2+}$ ion.

Answer 1

${Mn}^{2+}$

atomic number of $Mn=25$

electronic config $\Rightarrow {1s}^2{2s}^2{2p}^6{3s}^2{3p}^6{4s}^2{3d}^5$

${Mn}^{2+}\Rightarrow {1s}^2{2s}^2{2p}^6{3s}^2{3p}^6{4s}^0{3d}^5$

$n=5$

$\mu =\sqrt{n(n+2)}BM$

$=\sqrt{35}BM$