Question

The calculated spin only magnetic moment of $M{n}^{2+}$ ion is:

• A. $4.90\text{BM}$
• B. $5.92\text{BM}$
• C. $2.84\text{BM}$
• D. $3.87\text{BM}$

Answer 1

The correct option is B $5.92\text{BM}$

$M{n}^{2+}:\left[Ar\right]3d^5$
Number of unpaired electrons $\left(n\right)=5$
$\text{Spin only magnetic moment}=\sqrt{n(n+2)}\text{BM}$
$\mu =\sqrt{5(5+2)}\text{BM}$
$\mu =5.92\text{BM}$