Question

Calculate the magnitude of maximum work done (in $J$) in expanding 16 g of oxygen at 300 K and occupying a volume of $5d{m}^3$ isothermally untill the volume becomes $25d{m}^3$.
(Given $log5=0.6989$)

• A. 2159 J
• B. 2007 J
• C. 1055 J
• D. 2536 J

Answer 1

The correct option is B 2007 J

Reversible work is maximum work.
$\therefore W=-2.303nRT{\log }_{10}\left(\frac{V_2}{V_1}\right)$
where $V_2$ and $V_1$ are the final and initial volumes
n = moles of the gas
$W=2.303\times \frac{16}{32}\times 8.314\times 300\log \frac{25}{5}$
$W=2007.49J$