Question

Calculate the magnitude of spin angular momentum of an electron.

• A. $\frac{\sqrt{3}h}{4\pi }$
• B. $\frac{\sqrt{h}}{4\pi }$
• C. $\frac{\sqrt{3}h}{\pi }$
• D. $\frac{\sqrt{h}}{\pi }$

Answer 1

The correct option is A $\frac{\sqrt{3}h}{4\pi }$

The spin angular momentum of electron =$\frac{h}{2\pi }\sqrt{s(s+1)}$
Since s = 1/2,
The spin angular momentum of an electron =$\frac{h}{2\pi }\sqrt{\frac{1}{2}\times \frac{3}{2}}$
$=\frac{\sqrt{3}h}{4\pi }$