Question

calculate the mass of 3.011 10^23 molecules of water

Answer 1

6.022 $\times$10²³ molecules of water = 18 g of H₂O
3.011$\times$10²³ molecules = $\frac{18}{6.022\times {10}^{23}}\times 3.011\times {10}^{23}$

= 9 g