wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

Calculate the mass of lime obtained by heating 200g of 95% pure limestone.


A

100g

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

106.4g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

108.3g

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

110.3g

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

106.4g


Limestone is CaCO3(MM = 100u)

95% pure sample of 200g has (95100 × 200) = 190g of CaCO3.

CaCO3Δ CaO+CO2
(limestone) (lime)

100 g 56 g

100g of CaCO3 will yield 56g of lime

190g of CaCO3 will yield (190×56100)=106.4g of CaO


flag
Suggest Corrections
thumbs-up
36
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Stoichiometric Relation
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon