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Question

The mass of lime $$(CaO)$$ (in kg as the nearest integer) obtained by heating $$200$$ $$kg$$ of $$95\%$$ pure limestone $$(Ca{CO}_{3})$$ is:


Solution

Given, mass of pure lime stone in $$200$$ kg sample $$=$$ $$\dfrac{(95\times200)}{100}$$ $$=$$ $$190$$ kg.

Now, $$Ca{CO}_{3}\rightarrow CaO+C{O}_{2}$$

           $$ 100$$              $$56$$          $$ 44  $$   (Molecular mass)  

$$\therefore 100$$ $$kg$$ $$ Ca{CO}_{3} \equiv 56\ kg$$ $$CaO$$

$$\therefore 190\ $$ $$kg$$ $$\ Ca{CO}_{3} \equiv {\dfrac{56\times190}{100}} =106.4\ $$ $$kg$$ $$\ CaO$$.

So, nearest integer value is $$106$$.

Chemistry

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