Question

# The mass of lime $$(CaO)$$ (in kg as the nearest integer) obtained by heating $$200$$ $$kg$$ of $$95\%$$ pure limestone $$(Ca{CO}_{3})$$ is:

Solution

## Given, mass of pure lime stone in $$200$$ kg sample $$=$$ $$\dfrac{(95\times200)}{100}$$ $$=$$ $$190$$ kg.Now, $$Ca{CO}_{3}\rightarrow CaO+C{O}_{2}$$           $$100$$              $$56$$          $$44$$   (Molecular mass)  $$\therefore 100$$ $$kg$$ $$Ca{CO}_{3} \equiv 56\ kg$$ $$CaO$$$$\therefore 190\$$ $$kg$$ $$\ Ca{CO}_{3} \equiv {\dfrac{56\times190}{100}} =106.4\$$ $$kg$$ $$\ CaO$$.So, nearest integer value is $$106$$.Chemistry

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