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Question

The mass of lime obtained by heating 200g of 95% pure limestone is .


A
100 g
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B
108.3 g
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C
106.4 g
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D
110.3 g
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Solution

The correct option is C 106.4 g

Limestone is CaCO3(Molecular weight = 100u)

95% pure sample of 200g has (95100 × 200) = 190g of CaCO3.

CaCO3 Δ CaO + CO2
(limestone)       (lime)                  

 100 g              56 g              

  100g of CaCO3 will yield 56g of lime

190g of CaCO3 will yield (190×56100) = 106.4g of CaO


Chemistry

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