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Question

Calculate the mass of lime obtained by heating 200g of 95% pure limestone.


  1. 108.3g

  2. 110.3g

  3. 100g

  4. 106.4g


Solution

The correct option is D

106.4g


Limestone is CaCO3(MM = 100u)

95% pure sample of 200g has (95100 × 200) = 190g of CaCO3.

CaCO3Δ CaO+CO2
(limestone)              (lime)

100 g                      56 g

 100g of CaCO3 will yield 56g of lime

190g of CaCO3 will yield (190×56100)=106.4g of CaO

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