Calculate the mass per cent of calcium, phosphorus and oxygen in calcium phosphate $C a_{3} (P O_{4})_{2}$ .

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Solution

Mass per cent of calcium $= \frac{3 \times (a t o m i c m a s s o f c a l c i u m)}{m o l e c u l a r m a s s o f C a_{3} (P O_{4})_{2}} \times 100 = \frac{120 u}{310 u} \times 100 = 38.71 %$
Mass per cent of phosphorus $= \frac{2 \times (a t o m i c M a s s o f p h o s p h o r u s)}{m o l e c u l a r m a s s o f C a_{3} (P O_{4})_{2}} \times 100 = \frac{2 \times 31 u}{30} \times 100 = 20 %$
Mass per cent of oxygen $= \frac{8 \times (a t o m i c m a s s o f o x y g e n)}{m o l e c u l a r m a s s o f C a_{3} (P O_{4})_{2}} \times 100 = \frac{8 \times 16 u}{310 u} \times 100 = 41.29 %$

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