Calculate the mass percent of different elements in calcium phosphate.

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Solution

$C a_{3} {(P O_{4})}_{2}$
Total molecular weight $= 310.18 g / m o l$
$\Rightarrow 3 C a = \frac{120}{310.18} \times = 38.69 %$

$2 P = \frac{62}{310.18} \times 100 = 19.99 %$

$80 = \frac{128}{310.18} \times 100 = 41.27 %$
Hence, solved.

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