Calculate the maximum energy of a -particle emitted from a 14C nucleus which does not emit any -radiation- The masses of C-14 and N-14 isotopes are 14-003242 amu and 14-003074 amu respectively- 614C- 714N-1e0

The correct option is A 0.1564 MeV _6^14C⟶ _7^14N+_ 1e^0 Now, #160; Δ m = 14.003242 14.003074=0.000168 amu ∴ Energy emitted =Δ m × 9 ...

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Standard X

Physics

Nuclear Fusion

Calculate the...

Question

Calculate the maximum energy of a $β -$ particle emitted from a $^{14} C$ nucleus which does not emit any $γ$ -radiation. The masses of C-14 and N-14 isotopes are $14.003242$ amu and $14.003074$ amu respectively.
$_{6}^{14} C ⟶_{7}^{14} N +_{- 1} e^{0}$

0.1564

MeV

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0.1464

MeV

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0.1764

MeV

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None of these

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Solution

The correct option is A $0.1564$ MeV
$_{6}^{14} C ⟶_{7}^{14} N +_{- 1} e^{0}$

Now,

$Δ m = 14.003242 - 14.003074 = 0.000168 a m u$

$∴$ Energy emitted $= Δ m \times 931 = 0.1564 M e V$

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Similar questions

The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 amu, the binding energy of the helium nucleus will be [1 amu= 931 MeV]

Q. The following deuterium reactions and corresponding reaction energies are found to occur

^{14} N (d, p)^{15} N, Q = 8.53 M e V

^{15} N (d, α)^{13} C, Q = 7.58 M e V

^{13} C (d, α)^{11} B, Q = 5.16 M e V

The rotation

^{14} N (d, p)^{15} N

represents the reaction

^{14} N + d \to^{15} N + p

_{2}^{4} H e = 4.0026 a m u,_{1}^{2} H e = 2.014 a m u,_{1}^{1} H = 1.0078 a m u, n = 1.0087 a m u (1 a m u = 931 M e V)

The Q values of the reaction

^{11} B (α, n)^{14} N

Q. The mass of the nucleus

_{7} N^{14}

14.00000 a m u

. Calculate the binding energy per nucleon of

_{7} N^{14}

in MeV. Mass of proton

= 1.00759 a m u

, mass of neutron

= 1.00898 a m u

and

1 a m u = 931 M e V .

Q. Consider a nuclear reaction

A + B \to C

. A nucleus A moving with kinetic energy of 5 MeV collides with a nucleus B moving with kinetic energy of 3 MeV and forms a nucleus C in the exited state with excitation energy 10 MeV. The kinetic energy of nucleus C just after its formation is

\frac{5.3}{p} M e V

. Take masses of nuclei of A, B and C as 25 amu, 10 amu and 34.995 amu, respectively and 1 amu

= 930 M e V / c^{2} .

Find value of p___.

Q. A nucleus of mass 218 amu in free state decays to emit an

α

particle. Kinetic energy of the

α

particle emitted is 6.7 MeV. The recoil energy (in MeV) of the daughter nucleus is:

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Calculate the maximum energy of a β−particle emitted from a 14C nucleus which does not emit any γ-radiation. The masses of C-14 and N-14 isotopes are 14.003242 amu and 14.003074 amu respectively.146C⟶147N+−1e0

The correct option is A 0.1564 MeV146C⟶147N+−1e0Now, Δm=14.003242−14.003074=0.000168 amu∴ Energy emitted =Δm×931=0.1564 MeV

Calculate the maximum energy of a $β -$ particle emitted from a $^{14} C$ nucleus which does not emit any $γ$ -radiation. The masses of C-14 and N-14 isotopes are $14.003242$ amu and $14.003074$ amu respectively.
$_{6}^{14} C ⟶_{7}^{14} N +_{- 1} e^{0}$

The correct option is A $0.1564$ MeV
$_{6}^{14} C ⟶_{7}^{14} N +_{- 1} e^{0}$

Now,

$Δ m = 14.003242 - 14.003074 = 0.000168 a m u$

$∴$ Energy emitted $= Δ m \times 931 = 0.1564 M e V$