Calculate the maximum number of distinct diagonals that can be drawn in the hexagon in the above figure.

4

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9

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Solution

The correct option is D $9$
The total number of diagonals in n sided polygon is $\frac{n (n - 3)}{2}$ .
Substituting $n = 6$ gives us $\frac{6 (6 - 3)}{2} = 3 \times 3 = 9$ diagonals.

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Calculate the maximum number of distinct diagonals that can be drawn in the hexagon in the above figure.

The correct option is D 9The total number of diagonals in n sided polygon is n(n−3)2. Substituting n=6 gives us 6(6−3)2=3×3=9 diagonals.

The correct option is D $9$
The total number of diagonals in n sided polygon is $\frac{n (n - 3)}{2}$ .
Substituting $n = 6$ gives us $\frac{6 (6 - 3)}{2} = 3 \times 3 = 9$ diagonals.