If the number of diagonals that can be drawn in a polygon is 9, then what is the number of sides that the polygon has?

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
6

The number of diagonals that can be drawn in an `n' sided polygon is $\frac{n (n - 3)}{2}$ $∴$ $\frac{n (n - 3)}{2}$ = 9 $\Rightarrow$ n = 6

Suggest Corrections

Similar questions

Find the number of sides the polygon has if the number of diagonals that can be drawn in a polygon is 119.

Q. The number of diagonals that can be drawn from one vertex in a 9-sided polygon is ____.

The number of diagonals that can be drawn in a (n-3) sided polygon is 1/3 times the number of diagonals that can be drawn in an `n' sided polygon. The value of `n' is -

Q. If a polygon has

6

5 diagonals, then the number of sides of the polygon is

Q. The number of diagonals that can be drawn in a polygon of 100 sides is:

Join BYJU'S Learning Program

If the number of diagonals that can be drawn in a polygon is 9, then what is the number of sides that the polygon has?

The correct option is B 6 The number of diagonals that can be drawn in an `n' sided polygon is n(n−3)2 ∴ n(n−3)2 = 9 ⇒ n = 6

The correct option is B
6

The number of diagonals that can be drawn in an `n' sided polygon is $\frac{n (n - 3)}{2}$ $∴$ $\frac{n (n - 3)}{2}$ = 9 $\Rightarrow$ n = 6