The number of diagonals that can be drawn in a polygon of 100 sides is:

4850

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4950

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9900

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 4850
Formula for number of diagonals in 'n' sided polygon
$d = \frac{n (n - 3)}{2} = \frac{(100) (97)}{2} = 4850$

Suggest Corrections

Similar questions

Find the number of sides the polygon has if the number of diagonals that can be drawn in a polygon is 119.

The number of diagonals that can be drawn in an `n' sided polygon is 6 less than the number of diagonals that can be drawn in an (n + 1) sided polygon. The value of `n' is -

If the number of diagonals that can be drawn in a polygon is 9, then what is the number of sides that the polygon has?

Q. What is the number of diagonals which can be drawn by joining the angular points of a polygon of

100

sides?

In an `n' sided polygon, the number of diagonals that can be drawn is equal to the number of sides. Then `n' is -

Join BYJU'S Learning Program

The number of diagonals that can be drawn in a polygon of 100 sides is:

The correct option is A 4850Formula for number of diagonals in 'n' sided polygond=n(n−3)2=(100)(97)2=4850

The correct option is A 4850
Formula for number of diagonals in 'n' sided polygon
$d = \frac{n (n - 3)}{2} = \frac{(100) (97)}{2} = 4850$