Calculate the molar mass of the complex $C u S O_{4} .5 H_{2} O .$

249.5 g/mol

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

339.5 g/mol

No worries! We‘ve got your back. Try BYJU‘S free classes today!

269 g/mol

No worries! We‘ve got your back. Try BYJU‘S free classes today!

349.5 g/mol

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 249.5 g/mol
Molar mass of the complex $C u S O_{4} .5 H_{2} O$
$= (63.5 + 32 + 16 \times 4 + 10 \times 1 + 16 \times 5) g / m o l$
$= 249.5 g / m o l$

Suggest Corrections

Similar questions

C u S O_{4} .5 H_{2} O \to C u S O_{4} + 5 H_{2} O

C u S O_{4} + 2 K C N \to C u (C N)_{2} + K_{2} S O_{4}

2 C u (C N)_{2} \to 2 C u C N + (C N)_{2}

2 C u C N + 6 K C N \to 2 K_{3} [C u (C N)_{4}]

(Molar mass of K = 39 g / m o l, C u = 63.5 g / m o l)

[N i (C O)_{4}]

N i

2

(C u S O_{4} .5 H_{2} O)

C u = 63.5 g/mol

C u S O_{4} .5 H_{2} O .

[N i (C O)_{4}]

N i

Join BYJU'S Learning Program