Question

Calculate the molarity of 98% $H_2{SO}_4$ (d = 1.8 g/ml) by wt.

Answer 1

% of Sulphuric Acid in solution = 98%

means 98g of $H_{2}S{O}_4$ is present in 100g solution.

Molar mass = 98 g/mole

$\because$ No. of moles = $\frac{98}{98}$ = 1 mole ...(1)

Density of solution = $1.8g/c{m}^3$

$\therefore$ Volume = $\frac{100}{1.8}$ (ml) ...(2)

Molarity = $\frac{no.ofmolesofsolute}{volumeofsolution}$

from (1) & (2)

Molarity = $\frac{1}{100}\times 1.8\times 1000\left(inLvolume\right)$

$=18M$