Calculate the molarity of each of the following solutions- a 30 g of Co NO 32 -6 H 2 O in 4-3 L of solution b 30 mL of 0-5 M H 2 SO 4 diluted to 500 mL-

Molarity is given by: (a) Molar mass of Co (NO3)2.6H2O = 59 + 2 (14 + 3 × 16) + 6 × 18 = 291 g mol−1 ∴Moles of Co (NO3)2.6H2O = 0.103 mol Therefore, mol ...

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Standard IX

Chemistry

Mole Concept & Avogadro Number

Calculate the...

Question

Calculate the molarity of each of the following solutions: (a) 30 g of Co(NO₃)₂. 6H₂O in 4.3 L of solution (b) 30 mL of 0.5 M H₂SO₄ diluted to 500 mL.

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Solution

Molarity is given by:

(a) Molar mass of Co (NO₃)₂.6H₂O = 59 + 2 (14 + 3 × 16) + 6 × 18

= 291 g mol⁻¹

∴Moles of Co (NO₃)₂.6H₂O

= 0.103 mol

Therefore, molarity

= 0.023 M

(b) Number of moles present in 1000 mL of 0.5 M H₂SO₄ = 0.5 mol

∴Number of moles present in 30 mL of 0.5 M H₂SO₄

= 0.015 mol

Therefore, molarity

= 0.03 M

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Calculate the molarity of each of the following solutions: (a) 30 g of Co(NO3)2. 6H2O in 4.3 L of solution (b) 30 mL of 0.5 M H2SO4 diluted to 500 mL.

Calculate the molarity of each of the following solutions: (a) 30 g of Co(NO₃)₂. 6H₂O in 4.3 L of solution (b) 30 mL of 0.5 M H₂SO₄ diluted to 500 mL.