Question

Calculate the mole fraction and normality of solution if 10 gm 10 gm of H2SO4 is dissolved in 50 gm of water??

Answer 1

Dear student
number of moles =mass/molar mass
n_H2O = 50gm / 18gm/mol = 2.78 moles
n_H2SO4 = 10gm / 98gm/mol = 0.102 moles
mole fraction of H₂SO₄ = moles of H₂SO₄ /total moles
= 0.102 / (0.102+2.78)
= 0.0354
Normality = number of gram equivalent of solute / volume of solution in litre
equivalent weight of H₂SO₄ = molar mass / valence = 98/2 =49gm
Gram equivalent weight of H₂SO₄ = given mass / equivalent weight = 10gm/49gm = 0.204 gm
volume of solution in litre = mass/ density = 50gm/1gm/mL = 50mL = 0.05L
THUS normality(N) = 0.204gm/0.05L
= 4.1N
Regards