Calculate the molecular formula of compound which contains 20% Ca and 80% Br (by wt.) if molecular weight of compound is 200.(Atomic wt. Ca = 40, Br = 80)

C a_{1 / 2} B r

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C a B r_{2}

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C a B r

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C a_{2} B r

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Solution

The correct option is B $C a B r_{2}$
Elements % % / Atomic mass Simple ratio Simplest whole no.
Ca $20$ $20 / 40 = 0.5$ $1$ $1$
Br $80$ $80 / 80 = 1$ $2$ $2$

Hence : Empirical formula = $C a B r_{2}$

$n = \frac{200}{200} = 1$

Hence : Molecular formula = $C a B r_{2}$

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Q. A carbon compound contains 12.8% of carbon; 2.1% of hydrogen and 85.1% of bromine. The molecular mass of compound is 187.9. Calculate the molecular formula of the compound (Atomic mass H = 1.008, C = 12, Br = 79.9):

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Elements	%	% / Atomic mass	Simple ratio	Simplest whole no.
Ca	$20$	$20 / 40 = 0.5$	$1$	$1$
Br	$80$	$80 / 80 = 1$	$2$	$2$

Calculate the molecular formula of compound which contains 20% Ca and 80% Br (by wt.) if molecular weight of compound is 200.(Atomic wt. Ca = 40, Br = 80)

The correct option is B CaBr2 Elements% % / Atomic mass Simple ratio Simplest whole no. Ca2020/40=0.511 Br80 80/80=122Hence : Empirical formula = CaBr2n=200200=1Hence : Molecular formula = CaBr2

The correct option is B $C a B r_{2}$
Elements % % / Atomic mass Simple ratio Simplest whole no.
Ca $20$ $20 / 40 = 0.5$ $1$ $1$
Br $80$ $80 / 80 = 1$ $2$ $2$

Hence : Empirical formula = $C a B r_{2}$

$n = \frac{200}{200} = 1$

Hence : Molecular formula = $C a B r_{2}$