Calculate the molecular mass of the following:
$(N H_{4})_{2} C O_{3}$

Given: atomic mass of $N a = 23, H = 1, O = 16, C = 12, N = 14, M g = 24, S = 32$

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Solution

The relative molecular mass of - $(N H_{4})_{2} C O_{3} = N_{2} H_{8} C O_{3}$
$= 14 \times 2 + 1 \times 8 + 12 + 3 \times 16$
$= 28 + 8 + 12 + 48$
$= 96 g / m o l$

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Similar questions

(a) Define atomic mass unit.

(b) Calculate the molecular mass of the following :

(i) $C u S O_{4} .5 H_{2} O$ (ii) $(N H_{4})_{2} C O_{3}$

(iii) $(N H_{2})_{2} C O$ (iv) $M g_{3} N_{2}$

Given atomic mass of Cu = 63.5, H = 1, O = 16, C = 12, N = 14, Mg = 24, S = 32

Q. The molecular mass of

(N H_{4})_{2} C O_{3}

is:

Given atomic mass of H = 1, O = 16, C = 12, N = 14.

Calculate the relative molecular masses of (Use K = 39, Cl = 35.5, O = 16, C = 12, H = 1, Na = 23, N = 14, S = 32)
(a) potassium chlorate
(b) sodium acetate
(c) chloroform
(d) ammonium sulphate

Q. Calculate percentage of water of crystallization in :

M g S O_{4} . 7 H_{2} O

[Atomic masses of

M g = 24, S = 32, O = 16, H = 1]

Calculae the mass of 0.1 mole of each of the following :
(a) $C a C O_{3}$ ,

(b) $N a_{2} S O_{4} . 10 H_{2} O,$
(c) $C a C l_{2},$

(d) Mg.

(Ca = 40, Na = 23, Mg = 24, S= 32, C= 12, Cl = 35.5, 0 = 16, H = 1 )

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Calculate the molecular mass of the following:(NH4)2CO3Given: atomic mass of Na=23,H=1,O=16,C=12,N=14,Mg=24,S=32

The relative molecular mass of - (NH4)2CO3=N2H8CO3=14×2+1×8+12+3×16=28+8+12+48=96g/mol

Calculate the molecular mass of the following:
$(N H_{4})_{2} C O_{3}$

Given: atomic mass of $N a = 23, H = 1, O = 16, C = 12, N = 14, M g = 24, S = 32$

The relative molecular mass of - $(N H_{4})_{2} C O_{3} = N_{2} H_{8} C O_{3}$
$= 14 \times 2 + 1 \times 8 + 12 + 3 \times 16$
$= 28 + 8 + 12 + 48$
$= 96 g / m o l$