Question

Calculate the momentum of a particle which has a de Broglie wavelength of $2.5\times {10}^{-10}m$.
$(h=6.6\times {10}^{-34}kg{m}^2{s}^{-1})$.

Answer 1

Momentum $=\frac{h}{\lambda }$ (using de Broglie equation)
$=\frac{6.6\times {10}^{-34}}{2.5\times {10}^{-10}}$
$=2.64\times {10}^{-24}$ $kg$ $m$ ${sec}^{-1}$.