Question

Calculate the mutual inductance between two coils if a current $10A$ in the primary coil changes the flux by $500Wb$ per turn in the secondary coil of $200$ turns. Also determine the induced $e.m.f$ across the ends of the secondary coil in $0.5$ second:

Answer 1

given $I=10A$

$t=0.5A$

$\begin{array}{c}\varphi =500wb/turn\\ N=200\end{array}$

total flux $=500\times 200$

$={10}^{5}wb$

mutual inductance $=r^2$

induced emf $e=?$

$\begin{array}{c}Q=MI\\ m=\frac{Q}{I}=\frac{{10}^5}{10}\\ m={10}^{4}H\\ e=\frac{mdI}{dt}=\frac{{10}^5\times 10}{0.5}\\ e=2\times {10}^{6}V\end{array}$