Calculate the number of:(a)hydrogen atoms in 0.1 mole of sulphuric acid. (b)molecules in one kg of calcium chloride

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Solution

1. No. of molecules of H₂SO₄ in 1 mol = 6.023 $\times$ 10²³
2. So,No. of molecules in 0.1 mol of H₂SO₄ = 6.023 $\times$ 10²²
3. 1 molecule of H₂SO₄ contains 2 atoms of H.
4. So,Number of atoms in 0.1 mol of H₂SO₄ = 2 $\times$ 6.023 $\times$ 10²² = $12.046 \times 10^{22}$

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Calculate the number of:(a)hydrogen atoms in 0.1 mole of sulphuric acid. (b)molecules in one kg of calcium chloride

1. No. of molecules of H2SO4 in 1 mol = 6.023 ×1023 2. So,No. of molecules in 0.1 mol of H2SO4 = 6.023 × 1022 3. 1 molecule of H2SO4 contains 2 atoms of H. 4. So,Number of atoms in 0.1 mol of H2SO4 = 2 × 6.023 × 1022 = 12.046 × 1022

1. No. of molecules of H₂SO₄ in 1 mol = 6.023 $\times$ 10²³
2. So,No. of molecules in 0.1 mol of H₂SO₄ = 6.023 $\times$ 10²²
3. 1 molecule of H₂SO₄ contains 2 atoms of H.
4. So,Number of atoms in 0.1 mol of H₂SO₄ = 2 $\times$ 6.023 $\times$ 10²² = $12.046 \times 10^{22}$