Calculate the number of bricks each measuring 25 cm - 15 cm - 8 cm required to construct a wall of dimensions 19 m - 4 m - 5 m- when 10- of its volume is occupied -by mortar-

The correct option is C 6000 Volume of wall = 19 m × 4 m × #160;5 m =380 m^3 Volume of each brick =25 cm × # ...

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Standard VII

Physics

Volume of Regular Solids

Calculate the...

Question

Calculate the number of bricks each measuring $25$ cm $\times 15$ cm $\times 8$ cm required to construct a wall of dimensions $19$ m $\times 4$ m $\times 5$ m, when $10 %$ of its volume is occupied 'by mortar.

4000

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8000

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7000

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6000

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Solution

The correct option is C $6000$
Volume of wall $=$ $19$ m $\times 4$ m $\times 5$ m $= 380 m^{3}$

Volume of each brick $= 25$ cm $\times 15$ cm $\times 8$ cm $=$ $3000 c m^{2} = 0.003 m^{3}$
Number of bricks needed $= \frac{(V o l u m e o f w a l l) - (10 P e r c e n t \times V o l u m e o f w a l l)}{V o l u m e o f e a c h b r i c k}$
$= \frac{380 - (0.1 \times 380)}{0.003}$
$= 114000$

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Calculate the number of bricks each measuring 25 cm ×15 cm ×8 cm required to construct a wall of dimensions 19 m ×4 m ×5 m, when 10% of its volume is occupied 'by mortar.

The correct option is C 6000Volume of wall=19 m ×4 m ×5 m =380m3Volume of each brick=25 cm ×15 cm ×8 cm = 3000cm2=0.003m3Number of bricks needed =(Volumeofwall)−(10Percent×Volumeofwall)Volumeofeachbrick =380−(0.1×380)0.003 =114000

Calculate the number of bricks each measuring $25$ cm $\times 15$ cm $\times 8$ cm required to construct a wall of dimensions $19$ m $\times 4$ m $\times 5$ m, when $10 %$ of its volume is occupied 'by mortar.