Calculate the number of electrons lost or gained during the changes.
$3 F e + 4 H_{2} O \to F e_{3} O_{4} + 4 H_{2}$

Open in App

Solution

$3 F e + 4 H_{2} O \to F e_{3} O_{4} + 4 H_{2}$
Valancy of $F e$ in $F e_{3} O_{4}$ is $+ 2,$
lost electrons $= 2 \times 3 = + 6$ .

Suggest Corrections

Similar questions

3 F e + 4 H_{2} O \to F e_{3} O_{4} + 4 H_{2}

B a C l_{2} + N a_{2} S O_{4} \to B a S O_{4} + 2 N a C l

A l C l_{3} + 3 K \to A l + 3 K C l

\begin{matrix} C o l u m n - I & C o l u m n - I I R e a c t i o n & N u m b e r o f e l e c t r o n s l o s t o r g a i n e d (P) & M n (O H)_{2} + H_{2} O_{2} \to M n O_{2} + 2 H_{2} O & (1) & 8 (Q) & A l C l_{3} + 3 K \to A l + 3 K C l & (2) & 2 (R) & 3 F e + 4 H_{2} O \to F e_{3} O_{4} + 4 H_{2} & (3) & 3 (S) & 3 H_{2} S + 2 H N O_{3} \to 3 S + 2 N O + 4 H_{2} O & (4) & 6 \end{matrix}

3 F e + 4 H_{2} O \to F e_{3} O_{4} + 4 H_{2}

Join BYJU'S Learning Program