Calculate the number of electrons lost or gained the changes:
$F e (C N)_{6}^{- 4} + C r_{2} O_{7}^{- 2} \to F e^{+ 3} + C_{2} O_{4}^{- 2} + N O_{2}^{-} + C r^{+ 3}$

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Solution

$F e (C N)_{6}^{- 4} + C r_{2} O_{7}^{- 2} \to F e^{+ 3} + C_{2} O_{4}^{- 2} + N O_{2}^{-} + C r^{+ 3}$
$C r$ from $+ 7 \to + 3$
hence gained electrons = $4 \times 2 = 8$

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