Question

Calculate the number of grams of magnesium chloride that could be obtained from 17.0 g of $HCl$ when $HCl$ is reacted with an excess of magnesium oxide.

Answer 1

Balanced equation is:

$\underset{1mol}{MgO}+\underset{=73g}{\underset{(2\times 36.5)g}{\underset{2mol}{2HCl}}}\to \underset{=95g}{\underset{(24+71)g}{\underset{1mol}{MgC{l}_2}}}+\underset{1mol}{H_{2}O}$

73 g of $HC1$ produce $MgC{l}_2=95g$
1 g of $HC$I produce $MgC{l}_2=\frac{95}{73}g$
17 g of $HCl$ will produce $MgC{l}_2=\frac{95}{73}\times 17g=22.12g$