Calculate the number of millimoles and milliequivalents of ${C r_{2} O_{7}}^{2 -}$ ion in acid medium when $100 m L$ of $0.01 M {C r_{2} O_{7}}^{2 -}$ is reduced to $C r^{3 +}$ by $F e^{2 +}$ .

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Solution

$C r_{2} O_{7}^{2 -} 1 m o l + 14 H^{+} + 6 e^{-} 6 m o l \to 2 C r^{3 +} + 7 H_{2} O$
$∴ 0.01 M C r_{2} O_{7}^{2 -} \equiv 0.06 N C r_{2} O_{7}^{2 -}$
Number of millimoles $= M \times V = 0.01 \times 100 = 1$
Number of milliequivalents $= N \times V = 0.06 \times 100 = 6$ .

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