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Isotopes, Isotones and Isobars

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Question

Calculate the number of moles in 34 g of ${N H}_{3}$ . (Given atomic mass of $N$ = 14 u ; $H$ = 1 u)

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Solution

number of moles = $n = \frac{w e i g h t}{m o l e c u l a r w e i g h t}$
weight of the $N H_{3}$ =34 g
Molecular weight of $N H_{3} = 14 + 3 \times 1 = 17$
$∴ n = \frac{34}{17} = 2$

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Isotopes, Isotones and Isobars

Standard IX Chemistry

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