Calculate the number of moles present in $4.9 g$ of $H_{2} S O_{4}$ .

0.01

moles

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0.02

moles

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0.05

moles

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0.03

moles

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Solution

The correct option is D $0.05$ moles
Given that:

$4.9 g H_{2} S O_{4}$

atomic weight $= 2 + 32 + 4 \times 16$

$= 98 g / m o l$

Moles $= \frac{gram weight}{atomic weight}$

$= \frac{4.9}{98} = 0.05 m o l e s$
Option C is correct.

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